SSC CHSL 2022 PYQs

Question 1

The ratio of the ages of two friends is 7 : 9, while after 10 years it will be 19 : 23. What will be their average age 7 years from now?

Accepted Answer

Let current ages be 7x and 9x. After 10 years, (7x+10)/(9x+10) = 19/23. Solving gives x=5. Current ages are 35 and 45. After 7 years, ages are 42 and 52. Average = (42+52)/2 = 47. Wait, (7x+10)/(9x+10) = 19/23 => 161x + 230 = 171x + 190 => 10x = 40 => x=4. Current ages are 28 and 36. After 7 years, ages are 35 and 43. Average = (35+43)/2 = 39.

Question 2

Study the given graph and answer the following question.As per data available above in which of the given years was the percentage of the population affected by flue the minimum?

Accepted Answer

Observe the line graph to find the lowest point representing the percentage of population affected by flu. This point corresponds to the year 1990.

Question 3

Nikhil suffers a loss of ₹140 when he sells a perfume at 20% discount. Find the marked price of the perfume if the cost price is ₹380.

Accepted Answer

Loss is ₹140, CP is ₹380. SP = CP - Loss = 380 - 140 = ₹240. Since SP is 80% of MP (20% discount), MP = SP / 0.80 = 240 / 0.80 = ₹300.

Question 4

RA and RB are two tangents from a common point ‘R’ outside the circle with centre ‘O’, having a radius of 6 cm. If ∠ARB = 70°, find the measure of the angle AOB.

Accepted Answer

In quadrilateral OARB, angles at A and B are 90° (tangent-radius property). The sum of angles in a quadrilateral is 360°. So, ∠AOB = 360° - 90° - 90° - 70° = 110°.

Question 5

What is the volume of the largest right circular cone that can be cut out from a cube whose edge is 10 cm?

Accepted Answer

The largest cone has height and diameter equal to the cube's edge (10 cm). Volume = (1/3)πr²h. Substitute r=5 cm and h=10 cm to get (1/3)π(5²)(10) = 250π/3 cm³.

Question 6

The marked price of a toy was ₹4,875. Successive discounts of 28% and 30% were offered on it during a clearance sale. What was the selling price of the toy?

Accepted Answer

First discount: 4875 * (1 - 0.28) = 4875 * 0.72 = 3510. Second discount: 3510 * (1 - 0.30) = 3510 * 0.70 = 2457. So, the selling price is ₹2,457.

Question 7

The following Bar Chart shows the number of students enrolled in two Summer Camps A and B from 2014 to 2019. Study the charts carefully and answer the question that follows:For the years 2014 to 2019, what is the ratio of the total number of students enrolled for Summer Camp A to that for Summer Camp B?

Accepted Answer

Sum students for Camp A (2014-2019) = 310. Sum students for Camp B (2014-2019) = 470. The ratio A:B is 310:470, which simplifies to 31:47.

Question 8

The following pie chart shows the spending of a country on tourism in various districts during a particular year. Total spending of the country ₹15,62,000Study the pie chart and answer the following question.How much less money (in ₹) is spent on district C than on district E ?

Accepted Answer

District E spending is 20% and District C is 16%. The difference is 4% of the total. Calculate 4% of ₹15,62,000 to get ₹62,480.

Question 9

The surface area of a volleyball spherical is 100π cm2. Find the volume of air enclosed in the ball.

Accepted Answer

First, use the surface area formula (4πr²) to find the radius (r=5 cm). Then, calculate the volume using the formula (4/3πr³), which gives 500/3π cm³.

Question 10

The diameter of the base of a right-circular cylinder is 12 cm and the height of the cylinder is 2.45 times the radius of its base. Find the volume of the cylinder. [Useπ=‌227]

Accepted Answer

Radius (r) = 12/2 = 6 cm. Height (h) = 2.45 * 6 = 14.7 cm. Volume = πr²h = (22/7) * 6² * 14.7 = 1663.2 cm³.

Question 11

If (ab + bc + ca) = 0, then what is the value of(‌1a2−bc+‌1b2−ca+‌1c2−ab)?

Accepted Answer

Given ab + bc + ca = 0, substitute -bc = ab + ca into the first term. Similarly, substitute for -ca and -ab in the other terms. This simplifies each denominator to a common factor, leading to the sum being 0.

Question 12

In a circle, AB and CD are two diameters which are perpendicular to each other. Find the length of chord AC.

Accepted Answer

Since AB and CD are perpendicular diameters, triangle AOC is a right-angled isosceles triangle. Using Pythagoras theorem, AC² = AO² + OC². As AO = OC = radius (r), AC² = r² + r² = 2r². So, AC = r√2. Since AB = 2r, r = AB/2. Thus, AC = (AB/2)√2 = AB/√2.

Question 13

Ifx−‌1x=11, what is the value of(x4+‌1x4)?

Accepted Answer

Square (x - 1/x) to get x² + 1/x² = 11² + 2 = 123. Then square (x² + 1/x²) to get x⁴ + 1/x⁴ = 123² - 2 = 15129 - 2 = 15127.

Question 14

Under a sale offer for an item, Mahesh was offered 24% discount on the part of the marked price that was paid in cash, but was charged 1.5% on the part of the marked price paid through a credit card. If Mahesh paid 40% of the marked price in cash and the rest through a credit card and his total final payment was ₹6,391, what was the marked price of the item?

Accepted Answer

Let marked price be MP. Cash payment is 0.4MP with 24% discount, so 0.4MP * (1-0.24) = 0.304MP. Credit card payment is 0.6MP with 1.5% charge, so 0.6MP * (1+0.015) = 0.609MP. Total payment = 0.304MP + 0.609MP = 0.913MP. Given 0.913MP = 6391, so MP = 6391 / 0.913 = ₹7000.

Question 15

A sphere passes through the eight corners of a cube of side 14 cm. Find the volume (in cm3) of the sphere.Take π = 22/7

Accepted Answer

The sphere's diameter is the cube's space diagonal (a√3). So, radius R = (14√3)/2 = 7√3 cm. Volume = (4/3)πR³ = (4/3) × (22/7) × (7√3)³ = 4312√3 cm³.

Question 16

The given table shows the consumption of grains (in kilograms) by a village per day over the given set of years. Study the table and answer the following question.For which set of years (in options) is the combined consumption per day equal to that for the other set of years?YearRiceWheatMaizeBarley1998-20001815035262003-20051674439172008-20101693849252013-20151504551212018-2020147546324

Accepted Answer

Calculate the total consumption for each year set by summing all grain types. Compare the totals. 2003-2005 total is 16+74+43+91+7 = 231. 2013-2015 total is 15+0+45+51+21 = 231. Thus, they are equal.

Question 17

The difference between the compound interest and the simple interest on a given principal is ₹1,725 in 2 years and the rate of interest in both cases is 25% per annum, and in the case when interest is compunded, it is compounded annually. Find the principal.

Accepted Answer

Use the formula for the difference between CI and SI for 2 years: P(R/100)^2. Substitute the given values: 1725 = P(25/100)^2. Solve for P to get ₹27,600.

Question 18

Find the sum of money which when increased by 15% becomes ₹19,320.

Accepted Answer

Let the sum be X. X increased by 15% is X * (1 + 0.15) = 1.15X. So, 1.15X = 19320. Solving for X gives X = 19320 / 1.15 = 16800.

Question 19

Study the given table and answer the question that follows.The table shows the number of students doing various courses in various cities.CityMBAMCAM.Sc.M.Com.M.A.TotalAhmedabad123413841440128913326679Bengaluru115617831874100313407156Bhopal118713471532132114866873Chennai134214731129176516667375New Delhi123010981128186517777098Hyderabad145612341556165317897688Kolkata123917851865150417628155Which city has maximum number of student?

Accepted Answer

To find the city with the maximum number of students, simply look at the 'Total' column for each city and identify the highest value. Kolkata has the highest total of 8155 students.

Question 20

If 9 × 4 of 3 ÷ 2 - 5 × Q + 2 × 3 = 10, then find the value of Q.

Accepted Answer

Apply BODMAS: First 'of', then multiplication/division from left to right, then addition/subtraction. Simplify the equation to 54 - 5Q + 6 = 10, which gives 60 - 5Q = 10. Solving for Q yields Q = 10.