unit step

The bilateral z-transform of a discrete-time signal x[n] is X(z) = (1-a^2) / ((z-a)(z^-1 - a)) with 0 < a < 1, and the region of convergence a < |z| < 1/a. Let u[n] be the discrete...

Consider a continuous-time signal $$ x(t)=-t^2\{u(t+4)-u(t-4)\} $$ where $u(t)$ is the continuous-time unit step function. Let $\delta(t)$ be the continuous-time unit impulse funct...

If u(t), r(t) denote the unit step and unit ramp functions respectively and u(t)*r(t) their convolution, then the function u(t+1)*r(t-2) is given by

If u(k) is the unit step and $$\delta\left(k\right)$$ is the unit impulse function, the inverse z-transform of $$F\left(z\right)=\frac1{z+1}$$ for k>0 is:

A unit step voltage is applied at $$t = 0$$ to a series $$RL$$ circuit with zero initial conditions.