GATE 2019 Electronics & Communication Q34

Question

A single bit, equally likely to be 0 and 1, is to be sent across an additive white Gaussian noise (AWGN) channel with power spectral density $N_0/2$. Binary signaling, with $0 \mapsto p(t)$ and $1 \mapsto q(t)$, is used for the transmission, along with an optimal receiver that minimizes the bit-error probability. Let $\phi_1(t)$, $\phi_2(t)$ form an orthonormal signal set. If we choose $p(t) = \phi_1(t)$ and $q(t) = -\phi_1(t)$, we would obtain a certain bit-error probability $P_b$. If we keep $p(t) = \phi_1(t)$, but take $q(t) = \sqrt{E}\phi_2(t)$, for what value of E would we obtain the same bit-error probability $P_b$?

Answer

0

Answer

1

Answer

2

Answer

3