numerical-methods

Consider the following function double f (double x) { if ( abs (x * x – 3) < 0. 01) return x; else return f (x / 2 + 1.5/x); } Give a value q (to 2 decimals) such that f(q) will re...

What does the following algorithm approximate? (Assume m > 1, $$ \in > 0$$) x = m; y = 1; while(x - y > ε){ x = (x + y) / 2; y = m/x; } print(x);

The formula used to compute an approximation for the second derivative of a function $$f$$ at a point $${x_0}$$ is