order

The "order" of the following ordinary differential equation is ______. $d^3y/dx^3 + (d^2y/dx^2)^6 + (dy/dx)^4 + y = 0$

The "order" of the following ordinary differential equation is $\qquad$ . $$ \frac{d^3 y}{d x^3}+\left(\frac{d^2 y}{d x^2}\right)^6+\left(\frac{d y}{d x}\right)^4+y=0 $$

For the equation $\frac{d^3y}{dx^3} + x (\frac{dy}{dx})^{3/2} + x^2y = 0$ the correct description is

For the equation $${{{d^3}y} \over {d{x^3}}} + x{\left( {{{dy} \over {dx}}} \right)^{3/2}} + {x^2}y = 0$$ the correct description is

In the following partial differential equation, $\theta$ is a function of $t$ and $z$, and $D$ and $K$ are functions of $\theta$ $D(\theta)\frac{\partial^2\theta}{\partial z^2} + \...

The order and degree of a differential equation $${{{d^3}y} \over {d{x^3}}} + 4\sqrt {{{\left( {{{dy} \over {dx}}} \right)}^3} + {y^2}} = 0$$ are respectively

The degree of the differential equation $$\,{{{d^2}x} \over {d{t^2}}} + 2{x^3} = 0\,\,$$ is

The differential equation $${{{d^4}y} \over {d{x^4}}} + P{{{d^2}y} \over {d{x^2}}} + ky = 0\,\,$$ is