SBI PO 2017 PYQs

Question 1

5 12 23 43 79 ?

Accepted Answer

The pattern is: (previous number * 2) + (previous-to-previous number) - 3. So, (79 * 2) + 43 - 3 = 158 + 43 - 3 = 201 - 3 = 198. Wait, this is wrong. Let's re-evaluate. The pattern is: (previous number * 2) - (previous-to-previous number) + 3. So, (79 * 2) - 43 + 3 = 158 - 43 + 3 = 115 + 3 = 118. This is also wrong. Let's try another pattern. The pattern is: (previous number + previous-to-previous number) + difference between previous two. No, this is not working. Let's try the differences: 12-5=7, 23-12=11, 43-23=20, 79-43=36. The differences are 7, 11, 20, 36. The differences of these differences are: 11-7=4, 20-11=9, 36-20=16. This is 2^2, 3^2, 4^2. So the next difference of difference should be 5^2 = 25. So the next difference should be 36 + 25 = 61. So the next number is 79 + 61 = 140.

Question 2

Directions (Qs 41-45): Read the following table and answer the following questions.
Districts
Museum
Total visitors
(Male & Female)
Percentage of male out of total visitors
P
250
40%
Q
350
44%
R
375
60%
S
450
56%
T
300
55%
U
525
32%

Find the difference between the total number of male visitors from districts Q, R and S together to see the museum and the total number of female visitors from districts S,T and U together to see the museum?

Accepted Answer

Calculate total male visitors from Q, R, S. Calculate total female visitors from S, T, U. Subtract the smaller sum from the larger sum to find the difference.

Question 3

B is eighteen years older than A. The respective ratio of B’s age six years hence and C’s present age is 3 : 2. If at present C’s age is twice the age of A, what was B’s age four years ago?

Accepted Answer

Let A's age be x. B's age is x+18. C's age is 2x. B's age after 6 years is x+18+6 = x+24. Ratio (x+24)/2x = 3/2. Solving gives x=12. B's current age is 12+18=30. B's age four years ago was 30-4=26.

Question 4

256 252 225 209 84 ?

Accepted Answer

The pattern is subtracting squares of prime numbers: 256 - 2^2 = 252, 252 - 5^2 = 227 (error in question, should be 227), 227 - 7^2 = 178 (error in question, should be 178), 178 - 11^2 = 57 (error in question, should be 57). The given series has errors. Assuming the pattern is 256 - 2^2 = 252, 252 - 3^2 = 243, 243 - 5^2 = 218, 218 - 7^2 = 169, 169 - 11^2 = 48. The question provided is flawed.

Question 5

I.x2– 3x + 2 = 0II.2y2– 7y + 6 = 0

Accepted Answer

Solve both quadratic equations by factorization. For I, roots are x=1, 2. For II, roots are y=3/2, 2. Comparing all pairs, we find x ≥ y.

Question 6

Time taken by A alone to finish a piece of work is 60% more than that taken by A and B  together to finish the same piece of work. C is twice as efficient as B. If B and C together can complete the same piece of work in 1313days, in how many days can A alone finish the same piece of work?

Accepted Answer

Let (A+B)'s time be T. A's time is 1.6T. Efficiency ratio A:(A+B) = 1/1.6T : 1/T = 1:1.6. So B's efficiency is 0.6. C=2B, so C=1.2. (B+C) efficiency = 1.8. (B+C) takes 40/3 days, so total work = 1.8 * 40/3 = 24 units. A's efficiency is 1. A takes 24/1 = 24 days.

Question 7

I.3x2+ 4x + l = 0II.y2+ 5y + 6 = 0

Accepted Answer

Solve both quadratic equations for x and y. For I, x = -1, -1/3. For II, y = -2, -3. Comparing all possible pairs, x is always greater than or equal to y.

Question 8

Out of her monthly salary, Ridhispends 34% various expenses.From the remaining,she gives16th to her brother23rd to her sister and the remaining she keeps as savings. If the difference between the amounts she gave to her sister and brother was Rs. 10,260, what was Ridhi’s savings?

Accepted Answer

Let total salary be S. Remaining after expenses is 0.66S. Brother gets (1/6)*0.66S = 0.11S. Sister gets (2/3)*0.66S = 0.44S. Difference is 0.33S = 10260, so S = 31090.91. Savings = 0.66S - 0.11S - 0.44S = 0.11S = 3420.

Question 9

17 18.6 15.4 21.8 9 ?

Accepted Answer

The series alternates between adding and subtracting. The differences are +1.6, -3.2, +6.4, -12.8. Each subsequent difference is double the previous one. So, the next difference is +25.6. Add 25.6 to 9 to get 34.6.

Question 10

I.2x2+ 5x + 2 = 0II.y2+ 9y + 20 = 0

Accepted Answer

Solve both quadratic equations by factorization. For I, roots are -2 and -1/2. For II, roots are -4 and -5. Comparing all possible pairs, x is always greater than y.

Question 11

A bag contains 63 cards (numbered 1, 2, 3, ....... 63). Two cards are picked at random from the bag (one after another and without replacement),what is the probability that the sum of numbers of both the cards drawn is even?

Accepted Answer

For the sum to be even, both cards must be even or both must be odd. There are 31 even and 32 odd numbers. Calculate P(E,E) + P(O,O) = (31/63 * 30/62) + (32/63 * 31/62) = 11/21.

Question 12

I.x2– 7x + 10 = 0II.y2– 12y + 35 = 0

Accepted Answer

Solve both quadratic equations by factorization. For I, roots are x=2, 5. For II, roots are y=5, 7. Compare all combinations: x is sometimes less than y, sometimes equal.

Question 13

I.2x2+ 11x + 14 = 0II.4y2+ 12y + 9 = 0

Accepted Answer

Solve both quadratic equations for x and y. For equation I, roots are -2 and -3.5. For equation II, roots are -1.5 (repeated). Comparing these values, x is always less than y.

Question 14

Directions (Qs 49-53): Refer to the graph and answer the given questions.
Data regarding the number of students optingfor one of the five games at a Sports Academy(having a total strength of 1400 students)

What is the respective ratio between the total number of students opting for Cricket in 2012 and 2013 together and those opting for Volleyball in the same years together ?

Accepted Answer

Calculate total Cricket students (2012+2013) and total Volleyball students (2012+2013). Then simplify the ratio of these two sums to get 7:8.

Question 15

23.001 × 18.999 × 7.998 = ?

Accepted Answer

Approximate the numbers to the nearest integers: 23 × 19 × 8. Calculate 23 × 19 = 437. Then, 437 × 8 = 3496, which is closest to 3500.

Question 16

I.x2+ 14x + 45 = 0II.y2+ 19y + 88 = 0

Accepted Answer

Factorize both quadratic equations. For I, roots are -5, -9. For II, roots are -8, -11. Compare all combinations of x and y roots to find the relationship.

Question 17

33.99 ×√?+ 42.032 ×√?× (?)

Accepted Answer

The question is incomplete as it lacks the full expression to solve for the missing value. Without the complete equation, it's impossible to determine the correct answer.

Question 18

Directions (Qs 49-53): Refer to the graph and answer the given questions.
Data regarding the number of students optingfor one of the five games at a Sports Academy(having a total strength of 1400 students)

What is the average number of students opting for Cricket, Swimming and Volleyball in 2013?

Accepted Answer

Sum the number of students for Cricket (350), Swimming (250), and Volleyball (300) in 2013. Divide the total (900) by 3 to get the average, which is 300.

Question 19

94.95 × 13.03 +√35.98× 14.99 = 53 ×√?

Accepted Answer

Approximate the values: 95 × 13 + √36 × 15 = 53 × √?. This simplifies to 1235 + 6 × 15 = 53 × √?, so 1235 + 90 = 1325. Thus, 1325 = 53 × √?, which means √? = 1325/53 = 25. Therefore, ? = 25^2 = 625.

Question 20

I.2x2– 9x + 9 = 0II.y2– 7y + 12 = 0

Accepted Answer

Solve both quadratic equations for x and y. For I, x = 3, 3/2. For II, y = 3, 4. Compare the values to find the relationship.