SBI PO 2016 PYQs

Question 1

A and B start a business with respective investments of Rs. 10000 and Rs. 18000. After 8 months from the start of the business, B quits and C joins with Rs. 24000. If annual profit be Rs. 38250, what is A’s share in the profit?

Accepted Answer

Calculate the investment-time product for A, B, and C. A: 10000*12, B: 18000*8, C: 24000*4. Find the ratio of these products. A's share is (A's ratio / total ratio) * total profit.

Question 2

C is 40% efficient less than A.A and B together can finish apiece of work in 10 days. B and C together can do it in 15 days.In how many days A alone can finish the same piece of work?

Accepted Answer

Let total work be 30 units. (A+B)'s 1-day work = 3 units. (B+C)'s 1-day work = 2 units. C's efficiency is 60% of A's. Solving these equations yields A's 1-day work as 1.5 units. So, A takes 30/1.5 = 20 days.

Question 3

I.12x2– 23x + 11 = 0II.21y2– 20y + 4 = 0

Accepted Answer

Solve both quadratic equations for x and y respectively. Compare the roots obtained. For I, x = 11/12, 1. For II, y = 2/7, 2/3. No consistent relationship exists.

Question 4

What would be the compound interest accrued on an amount of Rs. 8400 at the rate of 12.5% per annum compounded annually at the end of 3 years? (Rounded off to two digits after decimal)

Accepted Answer

Calculate the amount using A = P(1 + R/100)^T. Subtract the principal from the amount to find the compound interest. A = 8400(1 + 0.125)^3 = 11960.16. CI = 11960.16 - 8400 = 3560.16.

Question 5

Ali deposited Rs. P in scheme A for 3 years at the rate of 10% per annum simple interest. He invested the amount received after 3 years in scheme B for 2 years which offered compound interest at the rate of 10% per annum. If the interest earned from scheme B was Rs. 819, what is the value of P?

Accepted Answer

Let the amount after 3 years in scheme A be A. For scheme B, CI = P'[(1+R/100)^T - 1]. Given CI = 819, R = 10%, T = 2 years. Calculate P' (principal for scheme B). Then, P' = P(1 + RT/100) for scheme A. Solve for P.

Question 6

619.002 – 134.99 – 14.998 –9.012= ?

Accepted Answer

Approximate the numbers to the nearest whole: 619 - 135 - 15 - 9. This simplifies to 619 - (135 + 15 + 9) = 619 - 159 = 460. The closest option is 459.

Question 7

I.x2+ 12x + 35 = 0II.7y2+ 32y + 16 = 0

Accepted Answer

Solve both quadratic equations. For I, x = -5, -7. For II, y = -4/7, -4. Comparing these values, we find that x is always less than y.

Question 8

In a box there are 8 red, 7 blue and 6 green balls. One  ball is picked up randomly.What is the probability that it is neither red nor green?

Accepted Answer

Total balls are 8+7+6 = 21. Neither red nor green means the ball must be blue. There are 7 blue balls. Probability = (Favorable outcomes) / (Total outcomes) = 7/21 = 1/3.

Question 9

439.97 ÷ 15.02 + 208.08 ÷ 8.01 – 16.01 = ?

Accepted Answer

Approximate the values: 440 ÷ 15 + 208 ÷ 8 - 16. This simplifies to 29.33 + 26 - 16, which is approximately 39.33. The closest option is 40, which is not given. Rechecking, 440/15 is 29.33, 208/8 is 26. So 29.33 + 26 - 16 = 39.33. The options are far off. Let's re-evaluate the question. The correct answer is 40. The options provided are incorrect.

Question 10

I.25x2+ 20x + 3 = 0II.4y2+ 11y + 6 = 0

Accepted Answer

Solve both quadratic equations for their roots. For I, x = -3/5, -1/5. For II, y = -3/2, -2. Compare all possible pairs of roots to determine the relationship.

Question 11

5 3 4 7.5 17 45 ?

Accepted Answer

The pattern is (previous number × 0.5) + 0.5, then (previous number × 1) + 1, then (previous number × 1.5) + 1.5, and so on. For 45, it's (45 × 3) + 3 = 135 + 3 = 138.

Question 12

4?×√226= 245.998 ÷ 8.001 + 929.99

Accepted Answer

Approximate the values: 4? × √225 ≈ 246 ÷ 8 + 930. This simplifies to 4? × 15 ≈ 30.75 + 930 ≈ 960.75. So, 4? ≈ 960.75 / 15 ≈ 64.05. Since 4^3 = 64, the answer is 3.

Question 13

A number is such that when it is multiplied by 6, it gives another number which is more than 168 as the original number itself is less than 168. What is 15% of the original number?

Accepted Answer

Let the number be x. The problem states 6x - 168 = 168 - x. Solving this gives 7x = 336, so x = 48. Then, 15% of 48 is (15/100) * 48 = 7.2.

Question 14

I.10x2– x – 24 = 0II.y2– 2y = 0

Accepted Answer

Solve both quadratic equations. For I, factorize 10x² – x – 24 = 0 to get x = 8/5, -3/2. For II, factorize y² – 2y = 0 to get y = 0, 2. Compare all possible pairs of x and y values to find the relationship.

Question 15

9 16 25 38 57 ?

Accepted Answer

The differences between consecutive terms are 7, 9, 13, 19. The differences of these differences are 2, 4, 6. The next difference should be 8, making the next term 19+8=27. So, 57+27=84.

Question 16

?% of (140.06 × 7.99 – 679.92) = 330.01

Accepted Answer

Approximate the values: (140 * 8 - 680) = (1120 - 680) = 440. So, ?% of 440 = 330. Thus, (330/440) * 100 = 75%.

Question 17

Dharma invested Rs. P for 3 years in scheme A which offered 12% per annum simple interest. She also invested Rs. (P + 400) in scheme B which offered 10% compound interest (compounded annually), for 2 years. If the amount received from scheme A was less than that received from scheme B, by Rs. 304, what is the value of P?

Accepted Answer

Calculate Amount from Scheme A: P + (P * 12 * 3)/100 = 1.36P. Calculate Amount from Scheme B: (P+400) * (1 + 10/100)^2 = (P+400) * 1.21. Set up equation: 1.21(P+400) - 1.36P = 304. Solve for P: 1.21P + 484 - 1.36P = 304 => -0.15P = -180 => P = 1200.

Question 18

I.x2– 5x + 6 = 0II.2y2– 15y + 27 = 0

Accepted Answer

Solve x² – 5x + 6 = 0 to get x = 2, 3. Solve 2y² – 15y + 27 = 0 to get y = 3, 4.5. Comparing all possible pairs, x ≤ y is the correct relation.

Question 19

8 5 6 10 21 ?

Accepted Answer

The pattern is: (previous number * 0.5) + 1, (previous number * 1) + 1, (previous number * 1.5) + 1, (previous number * 2) + 1. So, 21 * 2.5 + 1 = 52.5 + 1 = 53.5.

Question 20

40% of 859 + 86.01 ÷ 7.99 = ?

Accepted Answer

Approximate 40% of 860 as 344. Approximate 86.01 ÷ 7.99 as 86 ÷ 8 = 10.75. Summing these gives 344 + 10.75 = 354.75, which is closest to 355.