SBI PO 2016 PYQs

Question 1

518.002 – 44.99 + 8.998 – 8.012 = ?

Accepted Answer

Perform the operations sequentially: 518.002 - 44.99 = 473.012. Then, 473.012 + 8.998 = 482.01. Finally, 482.01 - 8.012 = 473.998, which approximates to 474.

Question 2

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. A student attempted all the 200 questions and scored in all 200 marks. The number of questions, he answered correctly was :

Accepted Answer

Let 'x' be correct answers and 'y' be wrong answers. x + y = 200 and 4x - y = 200. Adding equations gives 5x = 400, so x = 80.

Question 3

What is the average number of female members in gymnasium B taking all the years together?

Accepted Answer

Sum the female members for gymnasium B across all years: 100 + 110 + 105 + 115 + 100 = 530. Divide by 5 years to get the average: 530 / 5 = 106.

Question 4

What is the average number of applications received for subject A in 2008, 2009 and 2011?

Accepted Answer

Sum the applications for subject A in 2008 (200), 2009 (250), and 2011 (210). Total is 660. Divide by 3 years to get the average: 660/3 = 220.

Question 5

358.98 ÷ 15.02 + 450.15 ÷ 8.992 + 56.02 = ?

Accepted Answer

Approximate the numbers: 359 ÷ 15 + 450 ÷ 9 + 56. This simplifies to 23.93 + 50 + 56, which is approximately 24 + 50 + 56 = 130. The closest option is 130.

Question 6

A copper wire is bent in the form of an equilateral triangle and has area 121√3cm2.If the same wire is bent into the form of a circle, the area(incm2) enclosed by the wire is (take π =227)

Accepted Answer

First, find the side of the equilateral triangle using its area. Then calculate the perimeter, which is the wire's length. Use this length as the circle's circumference to find its radius, and finally calculate the circle's area.

Question 7

What is the average number of male members in gymnasium A taking all the years together?

Accepted Answer

Sum the male members for gymnasium A across all years (90+95+85+100+90 = 460). Divide the total by the number of years (5) to get the average: 460/5 = 92.

Question 8

58. If the respective ratio of total number of applications received for subjects A and B together in 2012 and 2013 is 4 : 5, what was the total number of applications received for subjects A and B together in 2013?

Accepted Answer

From the data, applications for A+B in 2012 are 300+220 = 520. Given ratio 2012:2013 is 4:5. So, 4 units = 520, 1 unit = 130. Thus, 5 units (2013) = 5 * 130 = 650.

Question 9

25% of 459 + 65.01 ÷ 5.02 =?

Accepted Answer

Approximate 25% of 459 as 1/4 of 460 = 115. Approximate 65.01 ÷ 5.02 as 65 ÷ 5 = 13. Summing these gives 115 + 13 = 128.

Question 10

What will be the ratio of petrol and kerosene in the final solution formed by mixing petrol and kerosene tha tare present in three identical vessels in the ratio 4 : 1, 5 : 2and 6 : 1 respectively?

Accepted Answer

Calculate petrol and kerosene quantities for each vessel. Sum petrol from all vessels and kerosene from all vessels. The final ratio is the sum of petrol to the sum of kerosene.

Question 11

By what per cent is the numberof male members in gymnasiumA in 2012 more thanthat of female members?

Accepted Answer

In 2012, male members in gymnasium A are 300 and female members are 250. Percentage more = ((300-250)/250) * 100 = (50/250) * 100 = 20%.

Question 12

A number is such that when it is multiplied by ‘8’, it gives another number which is as much more than 153 as the original number itself is less than 153. What is 25% of the original number?

Accepted Answer

Let the number be x. The problem states 8x - 153 = 153 - x. Solving this gives 9x = 306, so x = 34. Then, 25% of 34 is 0.25 * 34 = 8.5.

Question 13

In 2005, out of total number of applications received for subjects A and B together, only 30% were accepted. What was the total number of applications accepted for subjects A and B together in 2005?

Accepted Answer

From the data, total applications for A and B in 2005 are 210 + 200 = 410. Accepted applications are 30% of 410, which is (30/100) * 410 = 123.

Question 14

Mrs. Sharma invests 15% of her monthly salary, i.e., Rs. 4428 in Mutual Funds. Later she invests 18% of her monthly salary on Pension Policies and she also invests another 9% of her salary on Insurance Policies. What is the total monthly amount invsested by Mrs. Sharma?

Accepted Answer

15% of salary is Rs. 4428. So, 1% = 4428/15 = Rs. 295.2. Total investment is (15+18+9)% = 42% of salary. Thus, total investment = 42 * 295.2 = Rs. 12398.4.

Question 15

What is the difference between the total number of members in gymnasium A and B taking all the years together?

Accepted Answer

Calculate the total members for A and B separately across all years. Then, find the absolute difference between these two sums to get the answer.

Question 16

476 472 462 434 352 ?

Accepted Answer

The differences between consecutive terms are -4, -10, -28, -82. The pattern in these differences is (x * 3) - 2. So, the next difference is (-82 * 3) - 2 = -246 - 2 = -248. Thus, 352 - 248 = 104.

Question 17

In 2004, 30% of applications received for subject A and 20% of applications received for subject B were from international students. What was the total number of International applicants for subjects A and B together in 2004?

Accepted Answer

Calculate 30% of applications for A and 20% for B. Sum these two values to get the total international applicants. (30% of 170) + (20% of 200) = 51 + 40 = 91.

Question 18

23.999 × 9.904 × 16.997 = ?

Accepted Answer

Approximate the numbers to 24, 10, and 17. Multiply 24 × 10 = 240. Then, 240 × 17 = 4080. The closest option is 4100.

Question 19

At peresent Anu is six years younger than Charu and Charu is 10 years younger than Bilal. Six years hence, the respective ratio between Bilal’s age and Anu’s age will be 3 : 2. Find Charu’s present age.

Accepted Answer

Let Charu's age be C. Anu = C-6, Bilal = C+10. In 6 years: Anu = C, Bilal = C+16. Ratio (C+16)/C = 3/2. Solve for C to get 32 years.

Question 20

45000 1800 90 6 0.6 ?

Accepted Answer

The series follows a pattern of division by 25, then 20, then 15, then 10. The next division should be by 5. So, 0.6 / 5 = 0.12.