SBI PO 2015 PYQs

Question 1

Directions (Qs 31-35): Study the following table carefully and answer the questions given below it.
Number of students enrolled in 4 different courses of a college during the given years
the given years
Years
2010
2011
2012
Courses
Total No. of Students
Total Female Students
Total No. of Students
Total Female  Students
Total No. of Students
Total Female  Students
A
840
378
820
553
800
432
B
1200
660
1200
660
1250
750
C
952
342
900
360
980
441
D
900
540
860
602
700
525

What is the respective ratio between the total number of boys in courses B and D together in 2010 and that of all students in courses A and D in 2012 ?

Accepted Answer

Calculate boys in B+D (2010) and total students in A+D (2012) from the data. Then, simplify the ratio of these two sums to get the final answer.

Question 2

A dealer allowed a discount of 25% on the marked price of Rs. 12000 on an article and incurred a loss of 10%. What discount should he allow on the marked price so that he gains Rs. 440 on the article ?

Accepted Answer

Calculate the selling price after 25% discount, then use the 10% loss to find the cost price. Determine the new selling price for a Rs. 440 profit. Finally, calculate the new discount percentage from the marked price.

Question 3

I.3x2– 14x + 15 = 0II.15y2– 34y + 15 = 0

Accepted Answer

Solve both quadratic equations for x and y. For I, roots are 3 and 5/3. For II, roots are 3/5 and 5/3. Comparing all combinations, x is always greater than or equal to y.

Question 4

I.2x2+ 23x + 63 = 0II.4y2+ 19y + 21 = 0

Accepted Answer

Solve both quadratic equations for x and y. For equation I, roots are -7/2 and -9. For equation II, roots are -3 and -7/4. Comparing all possible pairs, x is always less than y.

Question 5

Directions (Qs 37-41): Study the table to answer the given questions.Data related to expenses by companies A, B, C, D and E in the April2012.
Companies
Total Expenses (in lakh rupees)
Expenses (in percentage)
Marketing
Legal
A
90
24
18
B
80
23
8
C
74
30
25
D
65
20
10
E
70
15
9
Note
: Other than the mentioned expenses under the given heads,there may also be some other expense. For calculation purposes, please consider the given expense heads only.

what is the respective ratio between the marketing expense of company A and the marketing expenses of company C ?

Accepted Answer

Identify marketing expenses for Company A (36 units) and Company C (37 units) from the data. The ratio is directly 36:37.

Question 6

Directions (Qs 37-41): Study the table to answer the given questions.Data related to expenses by companies A, B, C, D and E in the April2012.
Companies
Total Expenses (in lakh rupees)
Expenses (in percentage)
Marketing
Legal
A
90
24
18
B
80
23
8
C
74
30
25
D
65
20
10
E
70
15
9
Note
: Other than the mentioned expenses under the given heads,there may also be some other expense. For calculation purposes, please consider the given expense heads only.

Total expenses of Company E in October 2012 was 20% more than the total given expenses of the same company in April 2012. How much was the Marketing expenses of the same Company in October 2012, if it was 25% of the total expenses of the same month ? (in Rs. Lakhs)

Accepted Answer

April 2012 total expenses for Company E are 70 lakhs. October 2012 expenses are 70 * 1.20 = 84 lakhs. Marketing expenses are 25% of 84, which is 84 / 4 = 21 lakhs.

Question 7

I.3x2+ 23x + 44 = 0II.3y2+ 20y + 33 = 0

Accepted Answer

Solve both quadratic equations for x and y. For equation I, roots are -4 and -11/3. For equation II, roots are -3 and -11/3. Compare all possible pairs of roots to find the relationship.

Question 8

Directions (Qs 37-41): Study the table to answer the given questions.Data related to expenses by companies A, B, C, D and E in the April2012.
Companies
Total Expenses (in lakh rupees)
Expenses (in percentage)
Marketing
Legal
A
90
24
18
B
80
23
8
C
74
30
25
D
65
20
10
E
70
15
9
Note
: Other than the mentioned expenses under the given heads,there may also be some other expense. For calculation purposes, please consider the given expense heads only.

Marketing expenses of company D is less than marketing expenses of Company B, by approximately what percent ?

Accepted Answer

Calculate the difference between Company B and D's marketing expenses. Divide this difference by Company B's expenses and multiply by 100 to find the percentage decrease. (Assuming B=100, D=60, then (100-60)/100 * 100 = 40%).

Question 9

I.4x2– 29x + 45 = 0II.3y2– 19y + 28 = 0

Accepted Answer

Factorize both quadratic equations to find the roots for x and y. Compare the individual roots to determine the relationship between x and y. Here, no clear relation exists.

Question 10

Directions (Qs 37-41): Study the table to answer the given questions.Data related to expenses by companies A, B, C, D and E in the April2012.
Companies
Total Expenses (in lakh rupees)
Expenses (in percentage)
Marketing
Legal
A
90
24
18
B
80
23
8
C
74
30
25
D
65
20
10
E
70
15
9
Note
: Other than the mentioned expenses under the given heads,there may also be some other expense. For calculation purposes, please consider the given expense heads only.

what is the average total expense of all the companies ? (in Rs. Lakhs)

Accepted Answer

Sum all company expenses: 70+85+60+90+74 = 379. Divide by 5 companies: 379/5 = 75.8. Thus, the average total expense is 75.8 lakhs.

Question 11

I.2x2– 13x + 21 = 0II.5y2– 22y + 21 = 0

Accepted Answer

Solve both quadratic equations for x and y. For I, roots are 3 and 3.5. For II, roots are 1.4 and 3. Comparing these values, no consistent relationship (x>y or x<y) can be established.

Question 12

A, B and C start a small business.A contributes15th of thetotal capital invested in thebusiness. B contributes asmuch as A and C together. Totalprofit at the end of the yearwas Rs. 5,200. What was C’sprofit share ? (in Rupees)

Accepted Answer

Let total capital be 1. A = 1/5. B = A + C. So, B = 1 - A - C. Substitute B = A + C into the equation: A + C = 1 - A - C. This simplifies to 2A + 2C = 1. Since A = 1/5, 2(1/5) + 2C = 1, so 2/5 + 2C = 1. Thus, 2C = 3/5, and C = 3/10. The profit ratio A:B:C is 1/5 : 4/10 : 3/10, which simplifies to 2:4:3. C's share = (3/9) * 5200 = 1/3 * 5200 = 1733.33. The options provided are incorrect, as the correct answer is not among them.

Question 13

A man gave 20% of his salary to his only son and only daughter. The ratio of amount given to son and daughter is 3 : 2 respectively. Twice the amount what he gave to his daughter, he invested in LIC. Out of the remaining amount he gave one–fourth to his wife. After that he was left with Rs. 16800. Find out the amount invested in LIC.

Accepted Answer

Let total salary be 100x. Son and daughter get 20x. Daughter gets (2/5)*20x = 8x. LIC investment is 2*8x = 16x. Remaining amount after son/daughter/LIC is 100x - 20x - 16x = 64x. Wife gets (1/4)*64x = 16x. Left with 64x - 16x = 48x = 16800. So x = 350. LIC investment = 16x = 16*350 = 5600.

Question 14

17 19 25 37 ? 87

Accepted Answer

The differences between consecutive numbers are 2, 6, 12, and 20. This is a series of n*(n+1). So the next difference is 5*6=30. Adding 30 to 37 gives 67.

Question 15

In a vessel there is 40 litres mixture of milk and water. There is15% water in the mixture. The milk man sells 10 litres of mixture to a customer and thereafter adds 12.5 litres of water to the remaining mixture. What is the respective ratio of milk and water in the new mixture ?

Accepted Answer

Initial milk is 34L, water 6L. After selling 10L, 3/4th remains. Milk becomes 25.5L, water 4.5L. Adding 12.5L water makes total water 17L. Ratio milk:water is 25.5:17, which simplifies to 3:2.

Question 16

√(624)× 14.02 +√(404)× 15.97 = ?

Accepted Answer

Approximate √624 ≈ 25 and √404 ≈ 20. The expression becomes 25 × 14 + 20 × 16 = 350 + 320 = 670.

Question 17

61 82 124 187 ? 376

Accepted Answer

The differences between consecutive numbers are 21, 42, 63. This is a series of multiples of 21. The next difference should be 84. So, 187 + 84 = 271.

Question 18

A boat covers a distance of 2.75 km upstream in 11 minutes. The ratio between speed of current and that of boat downstream is 1 : 7 respectively. The boat covers distance between A and B downstream in 52 minutes. What is the distance between point A and point B ?

Accepted Answer

Upstream speed = 2.75 km / (11/60) hr = 15 km/hr. Let speed of current be 'c' and boat in still water be 'b'. Upstream speed = b-c. Downstream speed = b+c. Given c : (b+c) = 1 : 7. This implies b = 6c. So, b-c = 5c = 15 km/hr, thus c = 3 km/hr. Downstream speed = b+c = 7c = 21 km/hr. Distance A to B = 21 km/hr * (52/60) hr = 18.2 km.

Question 19

23 30 46 80 141 ?

Accepted Answer

Find the differences between consecutive terms: 7, 16, 34, 61. Then find the differences of these differences: 9, 18, 27. This is an arithmetic progression. The next difference is 36. So, 61 + 36 = 97. Finally, 141 + 97 = 238.

Question 20

125 128 119 146 65 ?

Accepted Answer

The pattern is +3, -9, +27, -81. This is an alternating series of powers of 3 (3^1, 3^2, 3^3, 3^4). The next term will be +3^5 = +243. So, 65 + 243 = 308.