SBI PO 2013 PYQs

Question 1

Directions (Qs 76-80): Study the table carefully to answer the questions that follow.
Monthly Bill (in rupees) of paid by three landline phone,
electricity, laundry and mobile phone paid by three different people in five different months
Month
Landline Phone
Electricity
Laundry
Mobile Phones
Ravi
Dev
Manu
Ravi
Dev
Manu
Ravi
Dev
Manu
Ravi
Dev
Manu
March
234
190
113
145
245
315
93
323
65
144
234
345
April
124
234
321
270
220
135
151
134
35
164
221
325
May
156
432
211
86
150
98
232
442
132
143
32
332
June
87
123
124
124
150
116
213
324
184
245
134
125
July
221
104
156
235
103
131
143
532
143
324
432
543

What is the respective ratio between the elctricity bill paid by Manu in the month of April and the mobile phone bill paid by Ravi in the month of June ?

Accepted Answer

Find Manu's April electricity bill (e.g., 5400) and Ravi's June mobile bill (e.g., 9800). Simplify the ratio 5400:9800 by dividing both by 200, resulting in 27:49.

Question 2

Directions (Qs 81-85): Study the following table carefully and answer the questions that follows :
C
hart showing schedule of train from Dadar to Bhuj and number of passengers boarding from each station
Station name
Arrival time
Departure time
Halt time (in minutes)
Distance travelled for origin (in km)
No. of passengers boarding the train at each station
Dadar
Starting time
12.05 a.m.
—
0 km.
437
Vasai Road
12.53 a.m.
12.56 a.m.
3 minutes
42 km.
378
Surat
4.15 a.m.
4.20 a.m.
5 minutes
257 km.
458
Vadodara
6.05 a.m.
6.10 a.m.
5 minutes
386 km.
239
Anand Jn.
6.43 a.m.
6.45 a.m.
2 minutes
422 km.
290
Nadiad Jn.
7.01 a.m.
7.03 a.m.
2 minutes
440 km.
132
Ahmedabad
8.00 a.m.;
8.20 a.m.
20 minutes
486 km.
306
Bhuj
5.40 p.m.
End. point
—
977 km.
None

What is the distance travelled by the train from Surat to Nadiad Jn. ?

Accepted Answer

This question requires specific knowledge of the distance between Surat and Nadiad Jn. The correct distance is 183 km, which is a factual recall.

Question 3

Directions (Qs 81-85): Study the following table carefully and answer the questions that follows :
C
hart showing schedule of train from Dadar to Bhuj and number of passengers boarding from each station
Station name
Arrival time
Departure time
Halt time (in minutes)
Distance travelled for origin (in km)
No. of passengers boarding the train at each station
Dadar
Starting time
12.05 a.m.
—
0 km.
437
Vasai Road
12.53 a.m.
12.56 a.m.
3 minutes
42 km.
378
Surat
4.15 a.m.
4.20 a.m.
5 minutes
257 km.
458
Vadodara
6.05 a.m.
6.10 a.m.
5 minutes
386 km.
239
Anand Jn.
6.43 a.m.
6.45 a.m.
2 minutes
422 km.
290
Nadiad Jn.
7.01 a.m.
7.03 a.m.
2 minutes
440 km.
132
Ahmedabad
8.00 a.m.;
8.20 a.m.
20 minutes
486 km.
306
Bhuj
5.40 p.m.
End. point
—
977 km.
None

What is the respective ratio between the number of passengers boarding from Vasai Road and from Ahmedabad in the train ?

Accepted Answer

To find the ratio, identify the number of passengers from Vasai Road and Ahmedabad from the provided data. Divide the Vasai Road count by the Ahmedabad count and simplify the fraction to its lowest terms.

Question 4

Directions (Qs 81-85): Study the following table carefully and answer the questions that follows :
C
hart showing schedule of train from Dadar to Bhuj and number of passengers boarding from each station
Station name
Arrival time
Departure time
Halt time (in minutes)
Distance travelled for origin (in km)
No. of passengers boarding the train at each station
Dadar
Starting time
12.05 a.m.
—
0 km.
437
Vasai Road
12.53 a.m.
12.56 a.m.
3 minutes
42 km.
378
Surat
4.15 a.m.
4.20 a.m.
5 minutes
257 km.
458
Vadodara
6.05 a.m.
6.10 a.m.
5 minutes
386 km.
239
Anand Jn.
6.43 a.m.
6.45 a.m.
2 minutes
422 km.
290
Nadiad Jn.
7.01 a.m.
7.03 a.m.
2 minutes
440 km.
132
Ahmedabad
8.00 a.m.;
8.20 a.m.
20 minutes
486 km.
306
Bhuj
5.40 p.m.
End. point
—
977 km.
None

In halt time (stopping time) of the train at Vadodara is decreased by 2 minutes and increased by 23 minutes at Ahmedabad. At what time will the train reach Bhuj ?

Accepted Answer

The net change in halt time is -2 minutes + 23 minutes = +21 minutes. The train will reach 21 minutes later than its original schedule. Since the original arrival time is not given, we assume it's 5:40 AM + 21 minutes = 6:01 AM.

Question 5

Directions (Qs 86-90): Study the table carefully to answer the questionsthat follow.
Maximum and minimum temperature (in degree Celsius)recorded on 1st day of each month of five different cities
Temperature
Month
Bhuj
Sydney
Ontario
Kabul
Beijing
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
1st Sep.
24
14
12
2
5
1
34
23
12
9
1st Oct.
35
21
5
-1
15
6
37
30
9
3
1st Nov.
19
8
11
3
4
0
45
36
15
1
1st Dec.
9
2
-5
-9
-11
-7
31
23
2
-3
1st Jan.
-4
-7
-11
-13
-14
-19
20
11
5
-13

What is the difference between the maximum temperature of Ontario on 1st November and the minimum temperature of Bhuj on 1st January ?

Accepted Answer

To solve this, first identify the maximum temperature for Ontario on November 1st and the minimum temperature for Bhuj on January 1st from the provided data. Then, subtract the smaller value from the larger value to find the difference.

Question 6

Directions (Qs 86-90): Study the table carefully to answer the questionsthat follow.
Maximum and minimum temperature (in degree Celsius)recorded on 1st day of each month of five different cities
Temperature
Month
Bhuj
Sydney
Ontario
Kabul
Beijing
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
1st Sep.
24
14
12
2
5
1
34
23
12
9
1st Oct.
35
21
5
-1
15
6
37
30
9
3
1st Nov.
19
8
11
3
4
0
45
36
15
1
1st Dec.
9
2
-5
-9
-11
-7
31
23
2
-3
1st Jan.
-4
-7
-11
-13
-14
-19
20
11
5
-13

In which month (on 1st day) is the difference between maximum temperature and minimum temperature of Bhuj second highest ?

Accepted Answer

The temperature difference in Bhuj is highest in December, followed by November. This is due to the clear skies and dry air post-monsoon, leading to significant diurnal variations.

Question 7

Directions (Qs 86-90): Study the table carefully to answer the questionsthat follow.
Maximum and minimum temperature (in degree Celsius)recorded on 1st day of each month of five different cities
Temperature
Month
Bhuj
Sydney
Ontario
Kabul
Beijing
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
Max.
Mini.
1st Sep.
24
14
12
2
5
1
34
23
12
9
1st Oct.
35
21
5
-1
15
6
37
30
9
3
1st Nov.
19
8
11
3
4
0
45
36
15
1
1st Dec.
9
2
-5
-9
-11
-7
31
23
2
-3
1st Jan.
-4
-7
-11
-13
-14
-19
20
11
5
-13

What is the respective ratio between the minimum temperature of Beijing on 1st September and the maximum temperature of Ontario on 1st October ?

Accepted Answer

Identify Beijing's minimum temperature on Sept 1st (15°C) and Ontario's maximum temperature on Oct 1st (25°C) from the data. The ratio is 15:25, which simplifies to 3:5.

Question 8

Directions (Qs 91-95): Study piechartand table carefully to answerthe questions that follow:
Pie-chart showing Percentagewise distribution of cars in four
different states
Total cars = 700
Distribution of Cars
Table showing ratio betweendiesel and petrol engine carswhich are distributed amongfour different states
State
Diesel Engine cars
Petrol engine cars
State-1
3
4
State-2
5
9
State-3
5
3
State-4
1
1

A bag contains 7 blue balls and5 yellow balls. If two balls areselected at random, what is theprobability that none is yellow?

Accepted Answer

Total balls are 12. Probability of selecting 2 non-yellow balls means selecting 2 blue balls from 7. Calculate combinations for favorable and total outcomes, then divide.

Question 9

Directions (Qs 91-95): Study piechartand table carefully to answerthe questions that follow:
Pie-chart showing Percentagewise distribution of cars in four
different states
Total cars = 700
Distribution of Cars
Table showing ratio betweendiesel and petrol engine carswhich are distributed amongfour different states
State
Diesel Engine cars
Petrol engine cars
State-1
3
4
State-2
5
9
State-3
5
3
State-4
1
1

A die is thrown twice. What isthe probability of getting a sum7 from both the throws ?

Accepted Answer

The possible pairs for a sum of 7 are (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) – 6 outcomes. Total outcomes for two dice are 6*6 = 36. Probability is 6/36 = 1/6.

Question 10

Directions (Qs 98-100): Study the information carefully to answer these questions.
In a team there are 240 members(males and females). Two-third of them are males. Fifteen percent of males are graduates. Remaining males are non-graduates. Three fourth of the females are graduates.Remaining females are non-graduates.

What is the difference betweenthe number of females who arenon-graduates and the numberof males who are graduates?

Accepted Answer

Identify non-graduate females and graduate males from the data. Subtract the smaller value from the larger value to find the difference. (e.g., 120 - 116 = 4)

Question 11

Directions (Qs 98-100): Study the information carefully to answer these questions.
In a team there are 240 members(males and females). Two-third of them are males. Fifteen percent of males are graduates. Remaining males are non-graduates. Three fourth of the females are graduates.Remaining females are non-graduates.

What is the ratio between the total number of males and the number of females who are non-graduates ?

Accepted Answer

Total males = 400. Non-graduate females = 50. The ratio is 400 : 50, which simplifies to 8 : 1.