SSC MTS 2019 PYQs

Question 1

In a certain code language, ‘LIP’ is written as ‘40’, ‘GILT’ is written as ‘51’. What is the code for ‘ROPE’ in that code language?

Accepted Answer

Assign numerical values to letters (A=1, B=2,...). Sum the values for 'LIP' (12+9+16=37) and add 3 (number of letters) to get 40. For 'GILT' (7+9+12+20=48), add 3 (number of letters) to get 51. Apply the same logic to 'ROPE' (18+15+16+5=54) and add 3 to get 57.

Question 2

Select the number that can replace the question mark (?) in the following series.12, 12, 24, 72, 288, ?

Accepted Answer

The series follows a multiplication pattern: 12 × 1 = 12, 12 × 2 = 24, 24 × 3 = 72, 72 × 4 = 288. So, the next term is 288 × 5 = 1440.

Question 3

Select the option in which the letters share the same relationship as that shared by the given pair of letters.JT : NX

Accepted Answer

The pattern is +4 for the first letter (J to N) and +4 for the second letter (T to X). Option 1, TP : XT, follows the same pattern: T (+4) = X and P (+4) = T.

Question 4

Study the given pattern carefully and select the number that can replace the question mark (?) in it.57968248?20

Accepted Answer

The pattern involves two alternating series. The first series is 5, 9, 8, 4, which is not immediately obvious. The second series is 7, 6, 2, ?, 20. The pattern for the second series is: 7-1=6, 6-4=2, 2- (-86) = 88, 88-68=20. So, the missing number is 88.

Question 5

Which two numbers need to be interchanged to make the following equation correct?3 + 4 - 6 ÷ 2 = 7

Accepted Answer

Interchanging 6 and 4 gives 3 + 6 - 4 ÷ 2 = 3 + 6 - 2 = 9 - 2 = 7. This makes the equation correct.

Question 6

In a certain code language, ‘RAPID’ is written as ‘LUJCX’. What is the code for ‘STARE’in that code language?

Accepted Answer

The pattern is -7, +8, -7, +8, -7 for each letter. Applying this to STARE: S(-7)=L, T(+8)=B, A(-7)=T, R(+8)=Z, E(-7)=X. So, STARE becomes LBTZX.

Question 7

A travels 15 km with a speed of 30 km/h. He travels another 25 km with a speed of 10 km/h. What is his average speed for the entire journey?

Accepted Answer

Average speed is total distance divided by total time. Calculate time for each segment (distance/speed), sum them, then divide total distance (15+25=40 km) by total time (0.5+2.5=3 hours) to get 40/3 km/h.

Question 8

The speed of a boat in still water is 8 km/h. If the speed of the stream is 2 km/h, then how much distance can be boat travel in two hours going upstream?

Accepted Answer

Upstream speed is boat speed minus stream speed (8 - 2 = 6 km/h). Distance = speed × time. So, 6 km/h × 2 hours = 12 km.

Question 9

What is the value of23of94+12÷541−13+14×(1+13)

Accepted Answer

First, simplify the expression within the parenthesis: (1 + 1/3) = 4/3. Then, perform multiplication and division from left to right, followed by addition and subtraction. This yields 3/2 + 2/5 - 1/3 + 1/3 = 3/2 + 2/5 = 19/10.

Question 10

The marked price and the cost price of an article are in ratio 5 : 4. If the profit earned by selling the article is 12.5%, then what is the discount percentage?

Accepted Answer

Assume CP=400, MP=500. Profit is 12.5% of CP, so SP = 400 * 1.125 = 450. Discount = MP - SP = 500 - 450 = 50. Discount percentage = (50/500)*100 = 10%.

Question 11

The sum of Rs. 500 becomes Rs. 600 in 2 years at a certain rate of simple interest. If the rate of interest is halved, then what amount will Rs. 500 give in 2 years?

Accepted Answer

Initial interest is Rs. 100 in 2 years. So, rate is 10%. Halving the rate makes it 5%. New interest on Rs. 500 for 2 years at 5% is Rs. 50. Total amount will be Rs. 500 + Rs. 50 = Rs. 550.

Question 12

The volume of a right circular cone is 1232cm3and its height is 24 cm. What is its curved surface area? (Takeπ= 22/7)

Accepted Answer

First, use the volume formula (1/3πr²h) to find the radius (r=7cm). Then, calculate the slant height (l=√(r²+h²)=25cm). Finally, use the curved surface area formula (πrl) to get 550cm².

Question 13

A alone can do a piece of work in 30 days. B alone can do the same work in 60 days. If they work together for five days, What fraction of the work will be left?

Accepted Answer

A's 1-day work = 1/30, B's 1-day work = 1/60. Together, their 1-day work = 1/30 + 1/60 = 3/60 = 1/20. In 5 days, they complete 5 * (1/20) = 1/4 of the work. Remaining work = 1 - 1/4 = 3/4.

Question 14

The data given below shows the marks obtained by various students.MarksNumber of students10 – 12612 – 14814 – 16516 – 18718 - 204What is the mean marks (Correct up to two decimal places) of given data?

Accepted Answer

Calculate the mid-point for each class interval. Multiply mid-points by frequencies, sum them up, and divide by total frequency to find the mean. (14.67)

Question 15

The speed of a car is 36 km/h. How much time (in minutes) will a bus traveling at one-fifth of the speed of the car take to cover a distance of 900 m?

Accepted Answer

Car speed is 36 km/h. Bus speed is 1/5th of car speed, so 7.2 km/h or 2 m/s. Distance is 900 m. Time = Distance/Speed = 900/2 = 450 seconds, which is 7.5 minutes.

Question 16

If P : Q = 5 : 2, then (2P – 3Q) : (3P – 5Q) is equal to:

Accepted Answer

Substitute P=5k and Q=2k into the expression (2P – 3Q) : (3P – 5Q). This simplifies to (10k - 6k) : (15k - 10k), which is 4k : 5k, or 4:5.

Question 17

The length, breadth and height of a cuboid are 15 cm, 12 cm and 11 cm respectively. The length is decreased by623%, the breadth increased by813%, whereas the height is kept unchanged. What is the change in the total area of the four side faces (considering the rectangle contained by the length and breadth as the base) of the cuboid?

Accepted Answer

Initial lateral surface area = 2h(l+b) = 2(11)(15+12) = 594 cm². New length = 15 - 15*(20/300) = 14 cm. New breadth = 12 + 12*(25/300) = 13 cm. New lateral surface area = 2(11)(14+13) = 594 cm². Thus, no change.

Question 18

An article is sold for Rs. 2070 at a 15% profit. If the article is sold for Rs. 1890, then what will be the gain/loss percent?

Accepted Answer

First, find the cost price (CP) using the initial selling price (SP) and profit percentage. CP = 2070 / 1.15 = Rs. 1800. Then, calculate the new profit/loss: (1890 - 1800) / 1800 * 100 = 5% gain.

Question 19

The length, breadth and height of a cuboid are 5 cm, 2 cm and 4cm respectively. What is the total surface area of the cuboid?

Accepted Answer

The total surface area of a cuboid is 2(lb + bh + hl). Substitute the given values: 2(5*2 + 2*4 + 4*5) = 2(10 + 8 + 20) = 2(38) = 76 cm².

Question 20

If x : y : z = 3 : 4 : 5 and x + y + z = 96, then what is the value of z?

Accepted Answer

Let x=3k, y=4k, z=5k. Summing them gives 3k+4k+5k = 12k. Since 12k=96, k=8. Thus, z=5k = 5*8 = 40.