SSC CHSL 2022 PYQs

Question 1

Which of the following numbers is divisible by 33?

Accepted Answer

For a number to be divisible by 33, it must be divisible by both 3 and 11. Check option 3: 1+8+5+5+9+2 = 30 (divisible by 3). (2-9+5-5+8-1) = 0 (divisible by 11).

Question 2

The table below gives the numbers (in thousand) of different types of geysers sold by a company in six consecutive years.YearTypesABCDE2007751221039895200810010210311210220091051081121091082010100189123102122201195123102124124201285145134134145What is the difference in the number of type B geysers sold in 2010 and 2012 ?

Accepted Answer

From the table, Type B geysers sold in 2010 were 189 (thousand) and in 2012 were 145 (thousand). The difference is 189 - 145 = 44 (thousand).

Question 3

Kuldeep offers his customers a discount of 10% on the marked price of a suitcase and he still makes a profit of 20%. What is the actual cost of the suitcase marked for Rs 2,500?

Accepted Answer

Selling Price = 2500 * (1 - 0.10) = 2250. Cost Price = Selling Price / (1 + 0.20) = 2250 / 1.20 = 1875. Thus, the actual cost is Rs 1875.

Question 4

The average runs of a cricket player in 20 matches is 30. If the average of the first 12 matches is 40, find the average of the last 8 matches.

Accepted Answer

Total runs in 20 matches = 20 * 30 = 600. Total runs in first 12 matches = 12 * 40 = 480. Runs in last 8 matches = 600 - 480 = 120. Average of last 8 matches = 120 / 8 = 15.

Question 5

If x - y = 25 and xy = 78, then what is the value of x2+ y2?

Accepted Answer

Use the identity (x - y)² = x² + y² - 2xy. Substitute the given values: (25)² = x² + y² - 2(78). This simplifies to 625 = x² + y² - 156. Therefore, x² + y² = 625 + 156 = 781.

Question 6

While selling to the retailer, a company allows 30% discount on the marked price of its products. If the retailer sells those products at marked price, his profit per cent will be ________.

Accepted Answer

Assume marked price (MP) is 100. Retailer buys at 30% discount, so Cost Price (CP) is 70. Selling Price (SP) is MP, which is 100. Profit = SP - CP = 100 - 70 = 30. Profit % = (Profit/CP) * 100 = (30/70) * 100 = 42 6/7%.

Question 7

How many numbers between 100 and 1000 are divisible by 17?

Accepted Answer

The first number > 100 divisible by 17 is 102 (17*6). The last number < 1000 divisible by 17 is 986 (17*58). Count numbers from 6 to 58: 58 - 6 + 1 = 53.

Question 8

Priya covers a certain distance by her car at a speed of 21 km/h and returns at a speed of 17 km/h. What is her average speed during the travel?

Accepted Answer

Use the formula for average speed when distance is constant: 2ab/(a+b). Substitute a=21 and b=17 to get 2*21*17 / (21+17) = 714/38 = 18.789 km/h, which is 18 15/19 km/h.

Question 9

If a + b + c =10 and ab + bc + ca = 30, then the value of a2+ b2+ c2is:

Accepted Answer

Use the identity (a+b+c)² = a²+b²+c² + 2(ab+bc+ca). Substitute the given values: 10² = a²+b²+c² + 2(30). This simplifies to 100 = a²+b²+c² + 60, so a²+b²+c² = 40.

Question 10

The population of a city increases at the rate of 10% per annum. If the population of the city was 2 crore in 2018, then the population of the city in the year 2021 was:

Accepted Answer

The population grows for 3 years (2018 to 2021) at 10% annually. Use the compound interest formula: P(1 + R/100)^T. So, 2 * (1.1)^3 = 2 * 1.331 = 2.662 crore.

Question 11

Compute the compound interest on ₹ 8,400 for one and half years at 12% rate of interest per annum, compounded half yearly.

Accepted Answer

For half-yearly compounding, rate becomes 12%/2 = 6% and time becomes 1.5 * 2 = 3 periods. Calculate amount A = P(1 + R/100)^T and then CI = A - P. This yields ₹1604.50.

Question 12

A mobile is marked at a price 25% above its cost price. At what discount percentage should it be sold to make a 10% profit?

Accepted Answer

Let CP be 100. MP = 125. For 10% profit, SP = 110. Discount = MP - SP = 125 - 110 = 15. Discount percentage = (15/125) * 100 = 12%.

Question 13

A thief is noticed by a policeman from a distance of 650 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 8 km and 10.5 km per hour, respectively. The distance (in metres) between them after 12 minutes is:

Accepted Answer

Calculate the relative speed (10.5 - 8 = 2.5 km/hr). Convert this to m/s (2.5 * 5/18). Multiply by time (12 minutes = 720 seconds) to find distance covered. Subtract this from initial distance (650m).

Question 14

Study the table and answer the question.Age of the child5years6 years7 years8 years9 yearsWeight (in kg)2022222725The sum of the weights of which two kids (referred to their ages) exceeds 50 kg?

Accepted Answer

Sum the weights for each option. For 8 and 9 years, 27 kg + 25 kg = 52 kg, which exceeds 50 kg. This is the correct option.

Question 15

The following table shows the number of students of seven colleges participating in extra-curricular activities. Study the table and answer the question that follows.Extra Curricular ActivitiesCollegeABCDEFGI15025045050350250150II5015015050505050III10050400125100500150IV250125350275250150150The colleges in which the minimum number of students participate in extra-curricular activities are :

Accepted Answer

Sum the students for each college: A=550, B=575, C=1350, D=500, E=750, F=950, G=500. Colleges D and G have the minimum total of 500 students.

Question 16

A shopkeeper sold an article for ₹1,326 after allowing a discount of 15% on its marked price. Find the marked price of the article.

Accepted Answer

Let MP be the marked price. Selling Price = MP × (100 - Discount%) / 100. So, 1326 = MP × (100 - 15) / 100. Calculate MP = 1326 × 100 / 85 = ₹1560.

Question 17

Study the following bar-chart and answer the question that follows.The bar-chart shows the sales of laptops (in thousands) over a period of four years.Find the percentage increase in sales from 2012 to 2013 , giving your answer correct to two places of decimal.

Accepted Answer

Sales in 2012 were 45 thousand and in 2013 were 65 thousand. Percentage increase = ((65-45)/45) * 100 = (20/45) * 100 = 44.44%.

Question 18

The average weight of 8 men is increased by 2 kg when one of them, whose weight is 90 kg, is replaced by another man. What is the weight of the new man?

Accepted Answer

The total weight increase is 8 men * 2 kg/man = 16 kg. The new man's weight is the old man's weight plus this increase: 90 kg + 16 kg = 106 kg.

Question 19

700 grams of cane sugar solution has 60% of sugar in it. How much sugar should be added to make it 75% in the solution?

Accepted Answer

Initial sugar is 420g (60% of 700g). Water is 280g. Let 'x' be added sugar. New sugar is (420+x)g, total solution (700+x)g. Set (420+x)/(700+x) = 0.75 and solve for x.

Question 20

What will be a single equivalent discount for successive discounts of 20%, 40% and 75% on the marked price of an item?

Accepted Answer

Calculate the final price after each discount: 0.80 * 0.60 * 0.25 = 0.12 of the original price. The single equivalent discount is 1 - 0.12 = 0.88 or 88%.