SSC CHSL 2022 PYQs

Question 1

Which of the following numbers will replace the question mark (?) in the given series?2, 22, 32, 42, 57, 87,162, ?

Accepted Answer

The pattern is based on differences: 22-2=20, 32-22=10, 42-32=10, 57-42=15, 87-57=30, 162-87=75. The second differences are: -10, 0, 5, 15, 45. This is a geometric progression (x3, x3, x3...). The next second difference is 45x3=135. So, the next first difference is 75+135=210. Thus, 162+210=372. Wait, the correct answer is 387. Let's re-evaluate. The differences are: 20, 10, 10, 15, 30, 75. The pattern is: 20, 10 (20/2), 10 (10*1), 15 (10*1.5), 30 (15*2), 75 (30*2.5). The multiplier increases by 0.5 each time. So the next multiplier is 3. 75*3 = 225. Therefore, 162 + 225 = 387.

Question 2

In a certain code language, “AN” is coded as “16”, and “NO” is coded as “212”. How will “US” be coded in that language?

Accepted Answer

The pattern is (position of first letter + 1) * (position of second letter + 1). For AN: (1+1)*(14+1) = 2*15 = 30. This is not 16. Let's re-evaluate. The pattern is (position of first letter * position of second letter) - (position of first letter + position of second letter). For AN: (1*14) - (1+14) = 14 - 15 = -1. This is not 16. Let's try another pattern. The pattern is (position of first letter + 1) * (position of second letter + 1) - (position of first letter + position of second letter). For AN: (1+1)*(14+1) - (1+14) = 2*15 - 15 = 30 - 15 = 15. This is not 16. Let's try another pattern. The pattern is (position of first letter + 1) * (position of second letter + 1) - (position of first letter + position of second letter) + 1. For AN: (1+1)*(14+1) - (1+14) + 1 = 2*15 - 15 + 1 = 30 - 15 + 1 = 16. For NO: (14+1)*(15+1) - (14+15) + 1 = 15*16 - 29 + 1 = 240 - 29 + 1 = 212. For US: (21+1)*(19+1) - (21+19) + 1 = 22*20 - 40 + 1 = 440 - 40 + 1 = 401.

Question 3

Which letter-group will replace the question mark (?) in the given series?78, 97, 54, ?, 30, 145

Accepted Answer

The series alternates between adding 19 and subtracting 43. 78 + 19 = 97, 97 - 43 = 54. So, 54 + 19 = 73, and 73 - 43 = 30. The pattern is incorrect. The actual pattern is: 78 + 19 = 97, 97 - 43 = 54. Then 54 + 67 = 121, and 121 - 91 = 30. This is also incorrect. The correct pattern is: 78 + 19 = 97, 97 - 43 = 54. Then 54 + 67 = 121, and 121 - 91 = 30. This is also incorrect. The correct pattern is: 78 + 19 = 97, 97 - 43 = 54. The next step should be 54 + X = ?. The differences are +19, -43. The next difference should be +67. So 54 + 67 = 121. Then 121 - 91 = 30. The differences are 19, 43, 67, 91. The differences between these differences are 24. So the next difference is 91 + 24 = 115. So 30 + 115 = 145. Thus, the missing number is 121.

Question 4

If 13 January 2006 is a Friday, then what will be the day of the week on 28 March 2008?

Accepted Answer

From Jan 13, 2006 to Jan 13, 2008, there are 2 years. 2008 is a leap year, so 2 odd days for 2007 and 2 odd days for 2008 (Jan 13 to Mar 28). Total odd days = 2 + (18+29+28)/7 = 2 + 75/7 = 2 + 5 = 7. So, 0 odd days. Friday + 0 = Friday.

Question 5

In a certain code language, ‘RACE’ is written as ‘AREC’, and ‘PEAK’ is written as ‘EPKA’. How will ‘CORE’ be written in that language?

Accepted Answer

The pattern involves moving the first letter to the second position, the second to the first, and keeping the third and fourth letters in their original positions. Applying this to CORE gives OCER.

Question 6

In a certain code language, ‘ACNE’ is written as ‘XZVM’ and ‘BODY’ is written as ‘LYBW’. How will ‘EVIL’ be  written in that language?

Accepted Answer

The pattern is that each letter is replaced by its opposite letter in the alphabet (A=Z, B=Y, C=X, etc.). Applying this, E becomes V, V becomes E, I becomes R, and L becomes O. So, EVIL becomes VEOR.

Question 7

Which letter-cluster will replace the question mark (?) to complete the given series?HSDA, IZQT, ?, KNQF, LUDY

Accepted Answer

The pattern for each letter's position is: 1st letter: +1 (H→I→J→K→L); 2nd letter: +7 (S→Z→G→N→U); 3rd letter: +13, -13, +13, -13 (D→Q→D→Q→D); 4th letter: -13, +13, -13, +13 (A→T→M→F→Y). Thus, the missing term is JGDM.

Question 8

Pointing to a woman in the picture, Vishal said, "Her mother is the wife of my sister's father". How is the lady related to Vishal?something went wrong

Accepted Answer

Vishal's sister's father is Vishal's father. His father's wife is Vishal's mother. So, the woman's mother is Vishal's mother, making the woman Vishal's sister.

Question 9

If ‘A’ denotes ‘+’, ‘B’ denotes ‘×’, ‘C’ denotes ‘–’ and ‘D’ denotes ‘÷’, then what will come in place of ‘?’ in the following equation?71 A 3 B 2 C 6 B (65 D 13) C 7 B 4 = ?

Accepted Answer

Substitute the symbols with operators: 71 + 3 × 2 - 6 × (65 ÷ 13) - 7 × 4. Follow BODMAS: first solve the bracket (65 ÷ 13 = 5), then multiplications, then additions and subtractions from left to right. This yields 71 + 6 - 30 - 28 = 77 - 58 = 19.

Question 10

Which of the following numbers will replace the question mark (?) in the given series?67, 83, 71, 91, 80, 118, ?

Accepted Answer

The series has two alternating patterns. The first pattern is 67, 71, 80, ... (adding 4, then 9). The second pattern is 83, 91, 118, ... (adding 8, then 27). The next number in the first pattern should be 80 + 16 = 96.

Question 11

For what angle D is ΔABC congruent to ΔDEF, given AC = 2.5 cm, BC = 5 cm, ∠C = 75°, DE = 2.5 cm and DF = 5 cm?

Accepted Answer

For ΔABC to be congruent to ΔDEF by SAS criterion, AC must correspond to DE, BC to DF, and the included angle ∠C to ∠D. Thus, ∠D must be 75°.

Question 12

A bought a toy at a discount of 35%. If he paid Rs. 975, then find the marked price of the toy.

Accepted Answer

Let the marked price be MP. A 35% discount means A paid 100% - 35% = 65% of MP. So, 0.65 * MP = 975. MP = 975 / 0.65 = 1500.

Question 13

The table below gives the numbers of students from five different colleges,Who participated in the Olympiads of five different subjects during a given year.SubjectsCollege ACollege BCollege CCollege DCollege EHindi110100125103112English9812080122105Maths130110250160180Science10010015020080GK182200120130183Find the difference between 'the range of the numbers of participants in the different Olympiads from College C' and 'the average number of participants per Olympiad from College E' during the given year.

Accepted Answer

College C range: 250 (Maths) - 80 (English) = 170. College E average: (112+105+180+80+183)/5 = 660/5 = 132. Difference = 170 - 132 = 38.

Question 14

In Class 8 of a school, the ratio of students playing cricket to those playing football is 27 ∶  13, while the ratio of those playing football to those playing hockey is 26 ∶  14. If the total number of students in Class 8 is 470, and each student plays exactly one game, find the percentage of students of the class playing cricket. [Give your answer correct to two decimal places.]

Accepted Answer

Combine ratios to get C:F:H as 54:26:14. Total ratio parts = 94. Cricket players = (54/94) * 470 = 270. Percentage = (270/470) * 100 = 57.45%.

Question 15

The difference between a number and the square root of the number is 2. The number is:

Accepted Answer

Let the number be x. The equation is x - √x = 2. Let √x = y, so x = y². The equation becomes y² - y - 2 = 0. Factoring gives (y-2)(y+1)=0. Since √x cannot be negative, y=2. Thus, x = y² = 2² = 4.

Question 16

The marked price of a mobile phone is Rs. 36,000. A shopkeeper gives a discount of 11% on the marked price. Further, if a customer purchases it through a credit card then the final discount increases to 15%. Pooja purchases it with a credit card. How much does she pay?

Accepted Answer

The marked price is Rs. 36,000. With a credit card, the total discount is 15%. So, Pooja pays 100% - 15% = 85% of the marked price. Calculate 85% of 36,000 to get the final price.

Question 17

In an election, there were three candidates: A, B and C. 10% of the eligible voters did not vote. Out of those who voted, 45% voted for A, 35% voted for B and the remaining 20% voted for C. 30% of the votes polled for A and 20% of the votes polled for B were later deemed invalid, while all the votes polled for C were deemed valid. If A got 882 more valid votes than B did, how many valid votes did C receive?

Accepted Answer

Let total voters be 100x. 90x voted. Valid votes for A = 90x * 0.45 * 0.7 = 28.35x. Valid votes for B = 90x * 0.35 * 0.8 = 25.2x. Difference = 3.15x = 882, so x = 280. Valid votes for C = 90x * 0.2 = 18x = 18 * 280 = 5040.

Question 18

Study the given table carefully to answer the question that follows.The following table given the information about the populations of five different cities in the year 2020.CityTotal Population% of Men% of Women% of childrenP4680045%35%20%Q4540035%50%15%R4200048%42%10%S3925042%42%16%T4620040%45%15%The number of women in city T forms approximately what percentage of the number of men in city P?

Accepted Answer

Calculate women in T (46200 * 45% = 20790) and men in P (46800 * 45% = 21060). Then, divide women in T by men in P and multiply by 100: (20790 / 21060) * 100 ≈ 98.72%.

Question 19

Ifsin‌⁡θ=‌1213, 0 <θ< 90°, then‌sin‌2⁡θ‌−cos‌2⁡θ‌2sin‌⁡θ‌.cos‌⁡θ‌×‌1tan‌2⁡θ=__________.

Accepted Answer

Given sinθ = 12/13. Using Pythagoras, cosθ = 5/13 and tanθ = 12/5. Substitute these values into the expression and simplify to get the result.

Question 20

If 2z = x + y, then the value of‌xx−z+‌yy−zis:

Accepted Answer

Given 2z = x + y, we can write x - z = z - y. Substitute this into the expression: x/(z-y) + y/(y-z) = x/(z-y) - y/(z-y) = (x-y)/(z-y). Since x-y = 2z-2y = 2(z-y), the expression simplifies to 2.